Recent content by crevoise

Yes, A, B and C are constant for the moment.

Hello, Thanks a lot for your answer. I think yet there is a small mistake on it, on the second change: $\displaystyle v=\frac{1}{(u-cx)^{m-1}} \implies v^{\ '}= \frac{1-m}{(u-c\ x)^{m}}\ u^{\ '}$ (4) I think it implies $\displaystyle v^{\ '}= \frac{1-m}{(u-c\ x)^{m}}(\ u^{\ '}-c)$ isn't it?

[FONT=Lucida Grande]Hello, [FONT=Lucida Grande]I have an equation of the following form: y'(t) + Ay(t) + By(t)^m + c = 0 [FONT=Lucida Grande]1/ With c=0, the equation is of the Bernoulli form, and might be integrated. [FONT=Lucida Grande]2/ With m = 2, it is a Riccati equation, which might be...

Thanks a lot for your two answers, really helpful! I should have thought about the binomial theorem... Thanks again

[FONT=Lucida Grande]Hello everyone. [FONT=Lucida Grande]I wish to get the solution to the following: [FONT=Lucida Grande]x'(t) = [A*exp(B*t)-C]^(m) [FONT=Lucida Grande]I can get the plotted solution by Matlab, but I wish to find the analytic solution by myself. [FONT=Lucida Grande]Does anyone...