Recent content by crouch88

Okay, now the first gradient becomes (-a√3) / (2x-a)... thanks Chaz! I hope this works.

Sorry guys! That was a typo! I basically just copied the whole response off my copy. I did take -√3 as gradient for the second pair of equations.

Homework Statement http://img1.uploadscreenshot.com/images/orig/5/12317385174-orig.jpg" The Attempt at a Solution Points: (0, 0); ( [x/2], [x√3]/2 ); (x, 0) For points (0, 0) and ( [x/2], [x√3]/2 ) Gradient = m = {[x√3]/2 - 0}/ {[x/2] - 0} = √3 m = (y-0)/(x-0) √3 = y/x...

okay okay wait wait... I solve y=a(squared) and y=9*x(squared) - a --- to get two equations Also when x=0 for the parabola, y=-a right? Uh okay...could you tell me then what I should do? OHHH I made a mistake in the diagram...y is not -0.3 ... y=-3

I just drew a diagram in ms paint... http://img1.uploadscreenshot.com/images/orig/5/12315022290-orig.jpg I just assumed that a=3 ... But I still don't get it

Homework Statement Here's the problem: refer to question no. 6 http://img1.uploadscreenshot.com/images/orig/5/12314183569-orig.jpg" Homework Equations I am not sure :S The Attempt at a Solution This, honestly, is a question which I have no clue how to go about... Thanks...