Recent content by cryptlogic

No, I do not think it is derived through that method...although it is still not entirely accurate for the above stated problem, but it is a start point to the solution.

t-> time for no bounce D-> distance for no bounce t1-> time for through b4 bounce d1-> distance for through b4 bounce t2->time for after bounce d2-> distance for after bounce V= D / t => t= D / V } } V=...