Recent content by cschear87

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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    So based on the circuit and resistors etc, we've gotten equations for KVL. How do those equations translate into the other equation i5 = i1 + i2 + i3? I have another tutorial on this tonight but I really want to make a bit more progress. For my own review I know that: Right Loop: 40i2 -80i3 = 0...
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    I'm just really frustrated that this isn't just popping into my head, second nature. I just can't seem to understand this 100%. Grr
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    Would you multiply i1, i2, i3 by the r in each equation? Ex: 20i1 - 40i2 = 0 20 (2) - 40 (1) = 0?
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    I'm not sure how the KVL equations tell me i1, i2, and i3. OR the source current.
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    Yes I think I understand. So the middle loop is 20i1 - 40i2 = 0
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    OK, I'll try again... Right Loop: 40i2 - 80i3 = 0 Middle Loop: 20i1 - 40i2 = 10 Left Loop: 10i5 + 20i1 = 10 Outside Loop: 10i5 + 80i3 =10? Power Dissipated is P=V^2/R I think. Is that the right formula? Voltage for each resistor would depend on which loop it's for?
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    So when I write out that i1 = 40i2 + 20i1 = 10 i2 = 80i3 - 40i2 = 0 i3 = 40i2 - 80i3 = 0 i5 = 10i5 + 20i1 = 10? I think I confused myself with the different equations...:redface:
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    So now that I have the equations and have some understanding, what exactly does that tell me about the currents? And how do I confirm this with power dissipated?
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    I thought that about the voltage but wasn't sure. So the right and middle loops have no voltage immediately in them so they have to balance out. But because on the left there's 10 volts going directly into that loop, the equation has to = 10? Is that right? The outside loop is... 10i5 + 80i3...
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    AC Voltage Waveform: Frequency, Time, RMS & Instantaneous Value

    OH I see, just got confused. Thank you!
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    So the right loop ie the 80Ω and 40Ω i3 and i2 =80i3 - 40i2 = 0 OR i2 = 2i3 Middle is the 20 and 40 ie i1 and i2. So i1 = 2i2 40i2 - 20i1 = 0 The left? Is there not voltage already there on the left as 10 volts is Vs. So I5 = 2i1 10i5 - 20i1 = 0?
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    lol, Well, I thought that 2 x 20 =40 and therefore 40-40=0. It all comes back to thinking things = 0. So is this to determine the current or the voltage? :confused:
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    I thought the equation had to =0. The 2 (both times) were because I thought the equation had to come to 0
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    Thought it had to = 0? So r5 is 10 So 2i5 = i1? - 2(10i5) = 20i1 or 2 (10) = 20
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    Using Kirchhoff's Laws to Find Currents, Source Current and Power Dissipated

    So, 2(20i1) - 40(i2) = 0?