Recent content by czng71

I think I have worked out a better method: Lx Ψ= 1/2 (L+ +L_)Ψ = 1/2 (L+Ψ + L_Ψ) = 1/2 [(L+)(Ψ200 +Ψ310+Ψ311+Ψ31-1) + (L_)(Ψ200 +Ψ310+Ψ311+Ψ31-1)] Plug in L+(Ym)=h(bar)√(l+m+1)(l-m) (Ym+1) and similarly for L_. Then we can get the answer? I found that Lx = √2h(bar) or 0. Is that...

After some work, I worked out that Lx = h(bar) /2 (0 1 0) for l = 1 .　　　　　　　　　　　　　　　　　　　　　　　　　　1 0 1 .　　　　　　　　　　　　　　　　　　　　　　　　　　0 1 0 But now there is the problem: in the question there is a linear combination of states where l = 1 and l = 0. I don't know how to deal with it. Thank you very...

I think (I guess?) I can find the eigenfunction of Lx first by constructing the matrices of raising and lowering operator, by the relation of Lx=1/2(L+ + L_). Then I can find the eigenvalues, which are the possible outcome when I measure Lx.

Homework Statement I am given a linear combination of wave function of HYDROGEN ATOM Ψ=1/2(Ψ200 +Ψ310+Ψ311+Ψ31-1), where the subscripts are n, l, m respectively. I was asked to find all the possible outcomes when measuring Lx and their corresponding probabilities. Homework Equations...