Recent content by D_J

But I want to know what physically happens. Why do we see a reversed spectrum? No matter where you put your eye, e.g., closer, higher, further back, it doesn’t matter, the spectrum is always reversed. Is it because our eyes trace the rays back in a straight line or is it because the rays...

You’re right, I could have misinterpreted his answer, but it’s unlikely. This is the diagram that I sent him. He said, “real images, such as those on the back of your eye, are images that can do work -- affect a photosensor, tickle your retina, expose a film emulsion. the light passed by a...

That is the main point of contention. Bruce is claiming that to see or photograph a reversed spectrum through a prism, the rays must overlap when exiting from the prism. They're saying that it cannot arise simply from tracing the rays back in a straight line. The guy from the Khan Academy...

Yeah, I agree with you. It’s just that the experts were David Briggs and Bruce MacEvoy. Their work on color perception is extensive, and they both disagree with me. David is a professor at the University of Technology in Sydney. Here’s their quotes and below is a sketch that Bruce sent me. “A...

Yeah, that’s what I thought, too, but I asked these two color experts, and they both said that my diagram doesn’t explain the reversed spectrum because, for example, an image in a mirror doesn’t require convergence at the image but on your retina. They both said that I need to redraw my...

Okay, they cross over when I trace them back, but that still doesn’t explain the image. In order for the color fringes to be reversed from left to right the rays have to cross over when they emerge from the prism, right?

Okay, here’s what I’ve got so far. Diagram A should be correct, but diagram B is what I see when I take the photo. If I let the light shine through the prism, it falls on the paper as in diagram A, but when it hits my retina or the camera, I see what’s shown in diagram B. The blue and red...

I know that red light has a lower index of refraction than blue light, but that’s not what I’m seeing. The blue light is where the red light should be. I can’t afford to join CHEGG. Any chance that someone would help me out for free? I’d really appreciate it. [Link to chegg removed by the Mentors]