I'm not physically building something, I am just designing a circuit schematic that would be capable of doing this with the parameters given haha. Thanks for the advice!
I know that iC=C(dVc/dt) and I know VL= L(diL/dt), so and inductor opposes instantaneous change in current and a capacitor opposes instantaneous change in voltage. I think I somewhat figured it out. I think maybe the 1 ms just is to confirm that the switch closes instantaneously. Thanks for...
Hey okay, so I have a 12V source which can provide a max of 10 mA, and I also have a switch that can go from open to close in 1 ms, How can I create an inductive circuit that will create a spark gap between electrodes that are 3mm apart? I did the math and found the breakdown voltage to be...
okay, so I think I see what your saying. I would use the same valued resistor on the opposite side (relative to the center pt of 0V) which would be my voltage divider for the -12V. I am a little confused on how that battery is producing a negative voltage though. Should I switch the polarity of...
so I need to add my potentiometer and resistor. If I put them in series and leave R as a variable setting it equal to 9V, I can solve for the resistance? I chose the 10k pot first, and I calculated using voltage division, the resistance to be 3333.33 ohms. Does this sound right?
I am stumped on a problem I have been working on. I am told to build a circuit that will have an output voltage between -9 and 9V.
We are given two 12 V batteries as power sources, and a choice between 3 potentiometers with values of 10k ohm, 20k ohm, and 50k ohm. We are allowed to use any...