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Oh... that makes a lot of sense! Thank you for your help!

ok but why the rounding to 1660 from 1657? That is kind of confusing to me so i really want to know to make sure I am not missing anything important.

How much work is done by the force? W= F * Δs * CosθW= (152N) * (13m) * Cos(33°) W=1976 * Cos(33°) W=1657.2 So I'm fairly confident I got this right since the answer is 1660J my question is Why would I have to round it up to 1660 to get it to Joules? I'm not really looking for help on the...

Thanks it's been super helpful already!

Awesome! Thanks a lot!

... about 1663 Newtons of force since it is a total of 2030N at a 215 degree angle.

Probably that it is about equal to the Horizontal force, and that the Net Force is 0

Probably that it is about equal to the Horizontal force, and that the Net Force is 0

The worker pushes downward and to the left on the box at an angle of 35°. The box has a mass of 135 kg. The box moves horizontally across the floor to the left at a constant velocity. The force applied by the worker is 2030 N∠215°. What is the value of the friction force?Fgravity · sin35° =...

Hi i am DaDoctor working on my Physics was told to introduce myself. I am a student looking for help.