ok but why the rounding to 1660 from 1657? That is kind of confusing to me so i really want to know to make sure I am not missing anything important.Engineer at UIC said:
DaDoctor said:
Oh... that makes a lot of sense! Thank you for your help!Engineer at UIC said:
The force has three sig figs, but I believe the distance the box was moved (13 m) only has two.Engineer at UIC said:
The formula for calculating work done by force is W = F * d * cos(theta), where W is work, F is force, d is the displacement, and theta is the angle between the force vector and displacement vector.
To calculate work done by a force, you need to multiply the force by the displacement and the cosine of the angle between the force and displacement vectors. For example, if the force is 152N and the displacement is 5m, and the angle between the two vectors is 0 degrees, the calculation would be: W = 152N * 5m * cos(0) = 760J. Therefore, the work done by the force is 760J.
The unit of measurement for work done by force is joules (J). This is derived from the formula W = F * d * cos(theta), where F is measured in newtons (N), d is measured in meters (m), and cos(theta) is unitless.
Yes, work done by a force can be negative. This occurs when the angle between the force and displacement vectors is greater than 90 degrees. In this case, the cosine of the angle will be negative, resulting in a negative value for work. This can also occur if the force is in the opposite direction of the displacement.
Work done by a force is the transfer of energy from one object to another. The work done by a force is directly proportional to the change in the object's kinetic energy. This means that if work is done on an object, its kinetic energy will increase by the same amount. Similarly, if work is done by an object, its kinetic energy will decrease by the same amount.