Dale's latest activity

I thought of another angle. Imagine the game is played simultaneously by three players, each with their own instance of the game. In...

In a nutshell. There are three boxes, 0, 1, and 2. The player picks a random box. 0, 1, or 2. If you simulate the game, then the player...

Jared Horvath was a math teacher who now has twenty years expericence as a cognitive neuroscientist. He states that his primary job now...

I suspect that either Horvath is simply wrong or that he is defining “conclusively show” in a personal way so as to make his conclusion...

I wish we had someone around here (UK) who wanted my Encyclopaedia Britannica! I've been trying to donate or sell it for years. It's...

So you are claiming that if I look into, for example, the journal Computers and Education, started in 1976, that I will not find one...

You could use the whole deck. The ace of spades is the prize and every other card is not. After the contestant chooses one card face...

I notice that if Alice is playing the game and has got as far as Monty opening a door when Bob walks in, Bob would have 50/50 odds on...

The probability is 1 for each of these rows. The car is behind door 1 and each set contains door 1. So for each set the probability of...

The possibilities are: Contestant chose the car, host opened the left hand goat door ##p=1/6##. Contestant chose the car, host opened...

It's not 50%. Among car-door pickers (1/3 of contestants), all stickers win, all switchers lose; Among goat-door pickers (2/3 of...

There are two choices. One has 1/3 chance having the car and the other has 2/3 chance to have the car. Your error is in thinking that...

if there are 100 doors, then you have only 1% chance of having picked the car door when you are offered the option to switch, and if you...

Except that you can be objectively shown to be wrong. The simulation in post 27 proves that switching doors will result in winning...

Only if the two options are equal probability, which they are not. Simply having two options does not mean that the probability is 1/2...