Hi,
I'd like to know the value that \Phi(x) of a normal distribution is approximated when x> 3,5.
I assume it is 1, since the value for x=3,49 is 0,9998...
But I got some answers at the university that it might be 0,5
Thanks
Is the minimum the same except for
\sum_{i=1}^n\!P(X_i \le t)
instead of the
\prod_{i=1}^n\!P(X_i \le t)
which would make
F_{M}(t) = n\frac{t}{\theta}
... ?