Recent content by Dan22

Homework Statement A turntable of radius "r" is spinning counterclockwise at an initial rate of ω. at t=0, its rotation rate begins to slow at a steady pace. the rotation finally stops at t=T. At what time is ωt^2 maximum. Express your answer in terms of T.

no problem, i think i got this it just has to do with finding at what time ω^2t is greatest pretty sure i got this, thanks for all your help,

so the answer is t=.2929T is that correct. pretty sure it is, and thank you very much you were very helpful. willing to help with part b?

7.0711 instead of 10, and i didn't expect that to be a fixed relationship but it seems to be. so for ω^2 to be one half of that ω=.70711ω though i expect that there is a neater form of that

man I'm feeling stupid right now, it would be at 1/3 of its speed at 2/3T and at 57% of its speed at .43T right?

for ω^2 to be half its size would ω= [α/(2r)]^.5 ? or am i just thinking myself in circles?

i'm still having trouble figuring out what ω needs to be for ω^2 to be half the size

do you mean when ω will be at 1/3ω and 57%ω. wouldn't that just be at T/3 and .57T. not sure why i would need those to be honest.

ω will be at half its original value at 1/2t. but what can i do with that?

i'm honestly not sure how to determine what ω needs to be nor when it will get there. ω^2 obviously has to be half as large but I'm not sure where to go from there

Homework Statement A turntable of radius "r" is spinning counterclockwise at an initial rate of ω. at t=0, its rotation rate begins to slow at a steady pace. the rotation finally stops at t=T. At what time during the time interval 0<t<T was the magnitude of the centripetal acceleration of a...