Recent content by Dan453234

Great i ended up doing this and got the right answer. Thanks!

I am getting .00011 if i do it using the approximation with average velocity. It marks this as incorrect.

Ok cool, I'm still a little confused how i would apply it to this problem however.

derivative?

I tried doing this but unfortunately this didn't give me the correct answer. Is there a more accurate way of doing this?

How would I perform the calculation with instantaneous speed?

Homework Statement Homework Equations 1/do+1/di=1/f The Attempt at a Solution I tried finding the distance of image at 27m and then at 30.5m and taking the difference but that didn't work.

Ok I think I got it. If we were to replace the ring with a coin with the heads facing us (for visual purposes), your saying if you rotate the coin with the heads facing left that's 75 degrees and even though it's now technically 180 degrees away from the field, you are taking the magnitude so...

I still don't see how the angle between the field and the moment is 90-theta degrees. Regardless I appreciate the help.

I'm still a little bit confused. I think it may be because of the whole y-axis part. Generally I under understand that if you have a loop that has its magnetic moment 15 degrees from the direction of magnetic field it would be |A||B|sin(15), but here (probably because of the confusing y-axis...

i get that sin(90-theta)= cos(theta) however, how would I know to use either. I don't see how the cross product would produce cos(theta)

Homework Statement I know the answer to this problem is IBNpir^2sin(90-theta). What I don't get, is why the angle is 90-theta. Homework EquationsThe Attempt at a Solution

Homework Statement So I understand that the magnetic flux is equal to the integral of (B dotted with dA) (new to the site don't know how to use math symbols). My question is, how come in some problems, is it ok to just say the magnetic flux is equal to the magnetic field times the area, while...