Recent content by Dangousity

So I = 1/2 m r2 instead.

Accord to my instruction "I" is I=Mr2 M=250kg r2=225cm = 2.25 meter Is this correct?

If the power to the motor is shut off while the motor is running at 3000 rpm, and a brake is applyed, how much heat in Joules will be dissipated in the brakes in order to bring the motor to a stop. Figuring W=1/2*I*w2 Sorry about the messy paper

Homework Statement Motor running, brakes applied. how much heat in joules will be dissipated? mass 250 kg diameter 30 cm 3000 rpm torque 120 N-m Homework Equations W=1/2 *I *w2 The Attempt at a Solution I keep going the route of: (1)/(2)*250*.3*315 1*125*.3*315...

Correct, I am attempting to do that

Homework Statement I have a motor, with an armature that has a mass of 250kg , and a diameter of 30 cm. Assuming the mass of the armature is evenly distributed, the rotational inertia of the armature is 22.5 kg-m^2. Now the motor accelerating unloaded, with armature current regulated so that...