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Angular acceleration of a motor

  1. Jan 21, 2010 #1
    1. The problem statement, all variables and given/known data
    I have a motor, with an armature that has a mass of 250kg , and a diameter of 30 cm. Assuming the mass of the armature is evenly distributed, the rotational inertia of the armature is 22.5 kg-m^2.
    Now the motor accelerating unloaded, with armature current regulated so that the armature develops a constant torque of 120 N-m, would be coming up to speed at 35.8 rad/sec^2? (Did I get this wrong?)
    Assume the torque stays the same, How long will it take for the unloaded armature to accelerate from 0 to 3000 rpm.
    2. Relevant equations
    T=Ia 22.5 kg-m^2(3000(pie)-15cm(pie))/(T)
    22.5(3000(pie)-.15m(pie))/(T)

    I think I am doing something wrong here cause I get stuck here.

    3. The attempt at a solution
     
  2. jcsd
  3. Jan 22, 2010 #2
    Mmm. Pie....

    It looks like you're trying to convert RPM to rad/s? I don't quite follow your equations.

    3000 revolution/min * 2pi rad/revolution * 1 min/60 s

    Should give you your angular speed.

    To figure out how long it takes, you can probably use the fact that net torque = dL/dt (the time rate of change of angular momentum) or you could use rotational kinematic equations to solve for the time.
     
  4. Jan 22, 2010 #3
    Correct, I am attempting to do that
     
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