Recent content by Daniokano

However this does not account for the gR^2/(2v^2) (given in the solution) Any ideas?

OK, so without use of conservation of energy, I assumed the height the mud left the tire is R. Now the velocity of the the mud is given v_t and the only acceleration effecting the mud is -g. y(t) = R + v_t*t - (g*t^2)/2 v(t) = v_t - g*t a(t) = - g Max height is reached when v(t) = 0...

My apologies, I didn't copy the question out correctly : The problem statement, all known variables and given data A car is stuck in the mud and mud is splashed around the rim of the tires. Assume that the radius of a tire is R and is spinning at a speed v>Rg. Without air resistance, show the...

Rg. Without air resistance, show the maximum height snow can reach is h_max=R+v^2/(2g)+gR^2/(2v^2) Solve using conservation of energy How do I start this problem? I assume all the initial kinetic energy ((mv^2)/2) from the spinning of the tire is translated to the gravitational potential energy...