Recent content by danny_smith

I know the steps to the solution but I don't understand why those steps are used, can anyone offer some input?

Hi Basic_Physics thanks for your input thus far, however your equation still results in the wrong answer.

p1/pg = 80*10^3/800*9.8 v1/2g =0 (because it cancels) z1=0 v2^2/2g = 0 (cancels) z2=-4 so p2 = (80*10^(3))/(800*9.8 +4)*800*9.8 = P2

By the way i think you got your Z2 mixed up it should be 4, not 200 since the slope is 1:50, either way you're answer is still wrong.

But solving that equation for Plower results in the wrong answer also.

Homework Statement Liquid, specific density 0.8, flows with velocity 4 m/s in a pipe that has a downward slope of 1:50. At a certain point in the pipe, a pressure gauge shows a pressure of 80 kPa. Determine the pressure at a point 200 m downstream of the gauge if: flow losses are ignored...