My ksΔL.
ks is 35000N/m * 0.014m = 490N = F
2*[490N] / 0.014m = ks'
ks' = 70000N/m which is twice the original like you said.
I still don't know how to get stiffness of a single interatomic "spring". Am I confused about what number to use? I believe the answer is a 2 digit N/m value and...
Stiffness of a single interatomic "spring"?
One mole of iron (6 x 10^23 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 x 10^-10 m. You have a long thin bar of iron, 2.8 m long, with a square cross...