Recent content by DarlingAly

Ah I see. Thanks. That was much more helpful than any of the other answers I got.

There is no x intercept. It's above the x-axis and it goes up. but if i didn't, I would probably do the quadratic formula

that makes no sense, and it doesn't answer my question. I know what x and y intercepts are. I know that if I want to be on the x-axis the y value has to be 0 and so forth. I want to know an equation I can use to calculate them from those three equations. Do I use the quadratic formula? or...

Hmm, okay thanks

Yes I'm trying to find the x and y intercepts of each of the three parabolas. But I don't really understand your method. Are you saying just to get each x an y alone and solve?

So here's the deal. I have three equations for three parabolas. I need to find the x and y inercepts, and a simplified radical to go with it. Here are the equations. Parabola one: y=(x-5)^2+6, Vertex: (5,6) Parabola two: y=2(x-1)^2-4, Vertex: (1, -4) Parabola three: y=-1(x+3)^2+8, Vertex...

Yeah I knew the standard form and the vertex form. I also knew the equations. It's just that I kept getting fractions while everyone else got the vertex to be a (3, -5) with the numbers i can't remember.. haha I just wanted to know if anyone did it different. Thanks!

Can someone help me with this problem? I already turned it in, knowing it was wrong, and now I want to know how to do it. they gave me three points and no equations and expected me to find the standard form and vertex form of the parabola. i don't remember what the points were, so let's just...