- #1
DarlingAly
- 8
- 0
So here's the deal. I have three equations for three parabolas. I need to find the x and y inercepts, and a simplified radical to go with it.
Here are the equations.
Parabola one: y=(x-5)^2+6, Vertex: (5,6)
Parabola two: y=2(x-1)^2-4, Vertex: (1, -4)
Parabola three: y=-1(x+3)^2+8, Vertex: (-3, 8)
Does anyone know how to set this problem up and what equations I should use?
Here are the equations.
Parabola one: y=(x-5)^2+6, Vertex: (5,6)
Parabola two: y=2(x-1)^2-4, Vertex: (1, -4)
Parabola three: y=-1(x+3)^2+8, Vertex: (-3, 8)
Does anyone know how to set this problem up and what equations I should use?