Recent content by datafiend

mark, thanks again!

Hi all, I'm having a problem simplifying this: [1/(1+x+h) - 1/(1+x)] / h How do you get the common denominators for the top 2 fractions? Thanks

I think -9+/-\sqrt{129}/-12 to negative infinity/positive infinity. Basically, the area between the pos and negative is excluded. Yes?

HI all, I have the equation, 6x^2-2>9x for which I'm to find the solution set in interval notation. I've rewritten the inequalty as 6X^2-9x-2=0. I tried to factor, but no go. Then I used the quadratic and got 9+/- rad(129)/-18. The answers I get for x are -1.1309 and .1309. The calculator...

Yeah. I got the other coordinates by substituting the y=-1 into the other equation. Thank you for your patience. I'm done for the day.

yes, I'm struggling with this... ok. i got y=0 or y=-1. at this point, do I just put the -1 into x and solve?

So, I get 4-y^2-y=4? Do I factor that out? Maybe use the quadratic formula?

Hi all. I'm really at a loss on how to find the "other" points of intersection for this system of equations: x^2-y=4 x^2+y^2=4 Obviously we have a parabola and circle. I have solved for x and got "2", and plugged that back into get "0". However the answer has 4...

i have the equation 7(3+7x) = 3(4-2x) so, I tried 7(3+7x)-3(4-2x)=0 ...

Hi all, $$f(x) = 3x^2+2x+10$$ I recognized that this a quadratic and used the quadratic formula. I came up with $$-1/3+-\sqrt{29}/3$$. But the answer has a $$i$$ for imaginary. When I was under the \sqrt{116}, I broke that down, but didn't realize there would be an $$i$$ Can someone explain...

I think intuitively that x CAN'T be a zero when it's in the denominator.

I typed in the problem wrong. It should be $$g(x)=(4+x^3)/x$$ Sorry.

I'm going through polynomials and the the problem: $$g\left(x\right)= (4+x^3)/3 $$ IS NOT A POLYNOMIAL FUNCTION. I don't get it. The answer says $$x\ne0$$, it's not a polynomial. How did you deduce that? Going down the rabbit hole...and it's the third week.

My mistake, the denominator SHOULD be in parentheses.

Homework Statement What's the domain of 14/x2-x-6, in interval notation? Homework Equations \underline{14}x2-x-6 The Attempt at a Solution [3, + infinity) [-2,- infinity) Sorry, I can't find the infinity symbol Thx