Recent content by dave2001

hahaha, this is the most aukward question i have ever come across, i just can't seem to get anything correct with it, haha

ct'=γ(ct-βx) with β=v/c, and γ=1/√1-β2 t'=γ(t-βx/c) using t = x/v = 1000c/v t'=y(1000c/v - βx/c) t'=y(1000c/v - vx/c2) t'=y(1000c-x/c2)

dont know :cry:

x'=1/1-β2 (x-βx)?

so ct'=γ(ct-βx) with β=v/c, and γ=1/√1-β2

why the suns frame?

keep coming out with 1.98x108ms-1

you mean in the Earth's frame, yeah i get the time is 1000c/v, as for the equation i don't know, i can't find anything in the textbook, I am sorry been working on this question since yesterday and its really getting to me, i keep getting stuck at this point :-(

3x108 x 750 = 2.25x1011m

im getting nowere either with the f-l contraction

yeah that was the first assumption i made distance x = 3x1011 m t'=750 t=1000 so in frame for t, v=3x108 for frame t' v=(3x1011)/750 gives 4x108ms-1 i got to feeling I am going about this the totally wrong way

the answer is 2.4x108 ms-1 cant figure out how to get to that

i got that far but v comes out at 4x108 ms-1 and it doesn't work

the diameter of the Earth's orbit is 3.0 x 1011 m. a spaceship crosses the orbit in 750s, as measured in the spaceship. what is the speed of the spaceship relative to the earth? (c = 3.0 x 108 ms-1

sorry, that's how mashed my head is, its not 3 108 that's the value for c, the diameter of the orbit is given as 3.0 x 1011 m