Recent content by Dave_1984

Hi, this is the last question of my assessment and I have spent over 10 hours looking at it and I really don't understand it. (I have had no problem with the other 25) I'm sure there is an easy and simple explanation as to where I'm going wrong? I can remember doing this in school and I'm...

Hi yes that is the question word for word, it has definitely confused me. I could use s = ut + 1/2at if it starts at rest that will give me the acceleration in ms-2 I have read that angular acceleration is measured it rad/s? 2 pi r= 9.42m 9.42 / 3 = 3.14ms-1 Thats about as far as I...

Hi, Yes that is the complete question so I guess it will start from rest if they are asking for the acceleration? My course information provides very short explanitions and no examples of angular acceleration and angular velocity. (ICS) As for what I have done so far - mainly just looking...

Homework Statement Calculate the angular acceleration and angular velocity of a 2kg object rotating in a circle of 1.5m radius in a time of 3s. Homework Equations w=v/r 2*pie*r The Attempt at a Solution Hi all, every attempt so far has been a failure, I just can't work out...

Thats great. So I now have \theta = sin-1 06/3 \theta = 11.53695903 t = mg/cos\theta t = 3x9.81/0.9797958971 t = 30.03686797N That definitely clears up everything, Thankyou very much for your help.

I have drawn a diagram that definitely helps. I have attached an example of the same question with different figures (notice the mistake cos14 is not 0.25?) I have also used this example to work out my problem and have written it to the side. Would you mind taking a look at this? Many...

Ok I'm very confused now, that's the way a simular problem just different mass and string lengh is worked out in my learning material - is that wrong then?

centrifugal

I think I finally have the answer. angle = tan-1 0.6/3 angle = 11.30993247 t=3x9.81/cos11.30993247 t=29.43/0.9805806757 t=30.01282886 So the tension on the string will be 30N? The main thing that has confused me is that i read on here that tan shouldent be used also there is a...

Ok so I think I have got it: mg=f 3x9.81=29.43N (force acting down on the bob) So now I need to work out the angle and get the force acting on the string?

I guess a force would be created with the momentum?

That would just be gravity?

Hi all, First of all I'd like to say thank you to you all for providing a great forum which has been a great help to me working through my ics home learning course. As i have learned on here and other places on the internet the information I have in my course materials is not always...