Recent content by David_Zheng

For simplifying terms, following algebra is applied: let:$$A=A$$ $$B=2\pi\sigma m\Omega\ell_{0}R$$and$$\Omega\left(z-t\right)=\tau$$ Equations you posted can be wirtten as: $$\bar{h}_{xx}^{TT}=A \cos\tau$$ $$\delta\bar{h}_{xx}^{TT}=B \sin \left(\tau-\phi\right)$$ Then...

Thank you Sir, it's pretty helpful!