Recent content by daysyworld

Hello, I've been two days trying to resolve this problem and I can't. I will try to translate it. To liquid, A and B have very similar boiling point. Because of that would be separate by liquid-liquid extraction with a dissolvent C. Calculate the minimum quantity of extract we have to...

Practically. Maybe here you can find the aswer. http://www.usatoday.com/weather/wbaromtr.htm Cheers.

I'm not agree whit your opinion. Water is polar and it doesn't andhere to glass. "[URL " Viscosity is a measure of the resistance of a fluid to deform under shear stress. It is commonly perceived as "thickness", or resistance to flow."[/URL] Because this resistance, the fluid who have high...

The kremser equation for how many stages ? 10 ? It's not a date, it's assumption.

Hi, he looks good to me a priori. My first option to draw the equilibrium line is taking real equilibrium dates, no spliting the tower, because the most important reason to do the operating line- equilibrium lin graphic is to obtain the real stages of the tower, but if they don't give you...

Hi, the reason is that the viscosity of Mercury is low 0.159*10^-2 (kg/ms). (for water = 0.105*10^-2 (kg/ms)) You can view more intuitively if you know for example the Glicerine viscosity (139.3 * 10^-2 ( kg/ms), three order of magnitude higher) :smile:

Hi, steel 1018 usually has between 0.15-0.20 % of Carbone, yes, the darker regions are perlite

Firstly you have to determine the radius of the circunference who contains the triangle. ( see the graphic below) - triangle is an equilateral triangle, because that the angles are 180/3= 60º If we draw the radius we have half angle ; 60/ 2 = 30 º Whe aply trigonometry ...

Could you copy here the wording of the absorption , and the dates you have to resolve it ? Maybe this way I can resolve your problem. Thanks.

If the operation line is also the equilibrium line, your tower have no stages and this never happens. ( To explain that clearly you can see this graphic. The stages are calculated always between the two lines ) If you think about you have said, you'll see that you have calculated the...

If I understand you correctly, the line you have dranw is the Equilibrium Line, to draw the operation line you have to aply this equation: G(Y1 - Y) = Ls(X1 - X) being 1 the bottom of the tower. Anyway you can obtain the same line joining the points (X1,Y1) [...

Hello, this is my first post here and I have to improve my English level, so sorry if I can't answer clearly your question. Firstly, If you say that you want to draw an equilibrium curve. The expresion y*=Hx, it's not a curve. It is a line. Usually if we work with a not concentrate solutions...