Recent content by ddsMom

That would be 310/(3*λ/2) = 310/1.44 = 215. That doesn't seem correct? It's been over 20 years since I've had Physics so I definitely appreciate any help.

Really?

I got it. The frequency of the second harmonic is two times the frequency of the first harmonic. The frequency of the third harmonic is three times the frequency of the first harmonic. so the answer is 969...I was going about it the hard way. Thank you for your time!

That's what I thought. What am I doing wrong? 3rd harmonic f=v/(λ*2/3) = 310/(.96/(2/3)) = 484Hz is my initial formula

I think I see my mistake. It should read... f=v/λ 2nd harmonic f=v/(λ/2) = 310/(.96/2) = 646Hz 3rd harmonic f=v/(λ*2/3) = 310/.64 = 484Hz Is that correct?

Homework Statement Tension = 400 N Mass = 4g Length = .96m What is the speed of the wave on a string? What is the frequency of the 3rd harmonic? Homework Equations v=√T/(m/L) v=fλ The Attempt at a Solution v=√400N/(.004kg/.96m) = 310m/s...am I correct? f=v/λ...

Changed my g to kg. Thank you so so much for confirming.

I did use v=sqrt[T/(m/L)] so I got v=sqrt[400N/(500g/m)] = .029 Am I on the right track?

So then would I find E Total first = 1/2k(A)2 + 1/2 m(v)2 =1/2(100)(.3)2 + 1/2(.4)(4.74)2 E total = 8.99 then subtract value of 1/4m(v)2?

Homework Statement A long string with a mass/length of 500g/m is placed under a tension of 400N. The string is then vibrated up and down with a period of .425sec. What is the wave speed? What is the wavelength of the resulting wave? I have no idea where to beginI would really...

Homework Statement A mass of .4 kg is connected to a spring with a spring constant of 100 N/m, slides on a frictionless horizontal surface in simple harmonic motion, Its maximum displacement is .3m? What is the maximum speed of the mass? What is the energy stored in gthe mass/spring...