Recent content by Ddvon

I thought that Mean squared error (MSE) MSE(\Theta) = E(\Theta - θ)^2 so MSE(\Theta) = V(\Theta) + bias^2 isn't it?

Hi. Let X_1 and X_2 be independent random variables with mean  μ and variance σ^2. \Theta = ( X_1 + 3X_2 ) /4 a) is it unbiased? b) what is the variance of the estimator? c) what is the mean squared error of the estimator? since there are four things, divided by 4...