Recent content by deadtreforest

thanks

i worked backwards with the anwser i was given but i messed up and put a divid sign in there the equation i got was mv^2t^2 but i have some doubts about the anwser.

i was trying mv^2/t i think its actually mv^2/ t^2

i used kg m/s / kg .78/.15=5.2 m/s /g 5.2/9.8= .53 1/2 g (m/s /g)^2=m 1/2x9.8x.53^2=1.38 it said that i got it right

In a typical golf swing, the club is in contact with the ball for about 0.0011 s. If the 45 g ball acquires a speed of 63 m/s, estimate the magnitude of the force exerted by the club on the ball.

A 0.150 kg ball is dropped from rest. If the magnitude of the ball's momentum is 0.780 kg·m/s just before it lands on the ground, from what height was it dropped?