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deadtreforest
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A 0.150 kg ball is dropped from rest. If the magnitude of the ball's momentum is 0.780 kg·m/s just before it lands on the ground, from what height was it dropped?
The concept is based on the principle of conservation of energy, which states that energy cannot be created or destroyed but can only be transferred from one form to another. In this case, the energy of the ball's initial height is transferred into its momentum as it falls, allowing us to calculate its original height.
The variables needed are the mass of the ball, its initial velocity, and the height from which it was dropped. These can be used in the equation p = mgh, where p is the momentum, m is the mass, g is the acceleration due to gravity, and h is the height.
The calculation can be very accurate if all variables are measured precisely and there are no external factors, such as air resistance, affecting the motion of the ball. However, there may be slight discrepancies due to human error or other unaccounted factors.
No, the calculation is only applicable in situations where the ball is dropped from rest and there are no external forces acting on it. If the ball is thrown or there is air resistance, the calculation will not be accurate.
The angle of the ball's trajectory does not affect the calculation as long as the height from which it was dropped remains the same. The momentum of the ball will still be the same regardless of its angle of motion.