When you take the surface integral of E*dA, do you get E*(area of sphere) which you then need to divide through by?
I have not had Vector Calculus, so a lot of the notation is odd to me.
Edit: I got E=\frac{Q}{4\pi \epsilon _0r_0{}^2} by dividing through by the area of a sphere.
Homework Statement
Imagine a solid, annular sphere. At the center of the hollow is a point charge +Q. The inner radius of the sphere is r0, and the outer radius is R. Assume the charge density p = p0/r (for r0 < r < R). Calculate using the integral form of Gauss's Law the electric field in all...