Recent content by decemberdays86
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Where Do I Start with First-Order Linear ODEs?
smart trick Tide! here's my mess of a solution: xy'+4x^2y-2ylny=0 y'-4xy=(-2ylny)/x Let \quad y = e^{g(x)} \implies y'=g'e^{g(x)} g'e^{g(x)}-4xe^{g(x)}= \frac {-2g(x)e^{g(x)}}{x} divide out e^g(x) and rearrange g'+\frac {2}{x}g=4x, Let \quad P(x) = 2/x \quad and \quad Q(x)=4x...- decemberdays86
- Post #9
- Forum: Introductory Physics Homework Help
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Where Do I Start with First-Order Linear ODEs?
thanks for your input saltdog. My prof seems to like asking questions where you need to recognize "chain-ruled" things. For example, I have to get used to identifying a product of two terms as the derivative of some compossite function... not cool hehe- decemberdays86
- Post #6
- Forum: Introductory Physics Homework Help
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Where Do I Start with First-Order Linear ODEs?
y'-4xy+2yln(y)/x=0 M(x,y)= -4xy \quad and \quad N(x,y)=2yln(y)/x err.. I'm taking Calc 3 and diff eq at the same time so I hope my partials are right... M_{y}=-4x \quad and \quad N_{x}=0 IntegFactor is defined as I(x) = e^{\int (M_{y} - N_{x})/N dx} according to my notes. yeah...- decemberdays86
- Post #3
- Forum: Introductory Physics Homework Help
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Where Do I Start with First-Order Linear ODEs?
First-Order Linear ODE help? This is my first post here. I'm still getting used to LATEX syntax so please forgive any mistakes. My question is on a simple differential equation... it doesn't appear to be exact or homogeneous... where do I start? thanks in advance. DD86- decemberdays86
- Thread
- Linear Ode
- Replies: 8
- Forum: Introductory Physics Homework Help