Recent content by Deckname

I've used the ##F_{avg}=\frac{\Delta P}{\Delta t}## and have arrived at the same result of ~##20000N##. I have calculated ##\Delta t## by using ##v^2={v_0}^2+2a \Delta x## to calculate the acceleration and plugged it in ##t=\frac{\Delta v}{a}## to get time. I calculated ##\Delta p## by taking...

Alright, I now realize I'm supposed to calculate the solution through F_avg=ΔP/Δt, but how do you calculate the change in momentum when not only the momentum changed, but also it's direction? I'm confused now.

Alright, thanks for pointing that out, I won't post handwritten stuff again. But then again I've explained what I've done in the OP (forgot to add I divided the work by distance, since F=W/d) and I've also attached a picture of the problem itself that I made in paint to be clearly readable.

I have calculated KE_i and KE_f, took the difference between the initial and final kinetic energy of the bullet to be equal to the work spent to overcome the friction, and divided it by the distance traveled, but arrive at around 20000N. The solution should be 9.5*10^7. Not sure what else to...

Hey, thanks for the reply. Appreciate it. I translated this problem from my native language, but yeah I'm not too sure either, but literally translated it means calculate the middle force of resistance, which I suppose means the average force of resistance, if we assume the force of friction...

I tried getting to the solution by the principle of conservation of energy. What goes in, must go out. If the final velocity, ie. the final kinetic energy is lower than what we started with, that energy difference must've been used to overcome the friction that lasted over some distance L...