Recent content by delyle

Yes, you're right. That minus sign in front of d\textbf{l} should be removed

Hello TSny, Thank you for your reply. I think I understand now. As far as the dimensional inconsistency, I had made a mistake in my explanation; the solution said that \int_{inner} d\textbf{l} =2a\hat{x} , which makes more sense, dimensionally. So, let's see if I follow you. Explicitly...

Homework Statement This is the problem 10.10 in Griffiths' Introduction to Electrodynamics, 3e (See attached image) I am only concerned about finding the retarded vector potential \textbf{A} Homework Equations \textbf{A}(r',t) = \frac{\mu_{0}}{4\pi} \int \frac{...