Demystifier's latest activity

E.g. by weighing scale.

As Einstein said, it is theory which determines what is measurable. According to the Newtonian theory of gravity, the gravitational...

Well, for those who like Albert's style of writing, it's probably good. Personally I'm not a fan of his style, but I believe there is...

I finished browsing Albert's "Quantum Mechanics and Experience" book, and studying its last chapter "8. Self-Measurement", where his...

The Albert's Chapter 8 is very interesting on its own right. It considers a version of the Wigner's friend thought experiment, by which...

On the other hand, a particle model is, itself, an approximation. If you believe QFT, there are only continuous fields at the root. And...

The geodesic equation $$\frac{d^2x^{\mu}}{d\tau^2} + \Gamma^{\mu}_{\alpha\beta} \frac{dx^{\alpha}}{d\tau} \frac{dx^{\beta}}{d\tau} = 0$$...

If you right-click on the equation in my post, you can see the ##\LaTeX##-code used to create it.

A lot of modern research papers investigates the possibility of aether...

That's infinite for any ##N##, not only for ##N=3##, due to the infinite last term ##i=N## in the sum.

I get from Wolfram Alpha 44.676683503771391589009225229630072178116008914652013623324856498 Calculation

I get from Wolfram Alpha 1.93277 Calculation 1 I get with else original values 4.23555 Calculation 2

That is in accordance with the result by OP, who obtained ##KE=E-M=M##, which implies ##E=2M##. This demonstrates that my removal of the...

Interesting! How much the last term ##i=N## contributes to the full sum? What happens if you take ##v=1## but compute the sum only up to...

Also note that the constraint of constant density per a local, comoving observer, means adding particles to outer rings as they are sped...