Recent content by dennish00a

OK, I think I figured this out. I believe that nothing matters except the angle the cable makes with the edge of the mirror. When this angle is the same on both sides, then each side has the same force pulling on a cable with the same configuration, and everything should cancel out, I believe...

This is a question from a mathematically-inclined homeowner who knows he /should/ be able to figure it out, but can't. I need to hang a heavy mirror in a house in Berkeley, CA, which is a seismically-active area. The mirror has a cable on the back of it attached to two sides of the mirror...