Recent content by Determined77

Sorry if I'm dense but I'm not sure what happens after I do that, or what it looks like... If I took sin-1 from both sides would I get 2x=1 and Sin-1(1) or 90 degrees?

Ok this is my first post...so bear with me :smile: My problem is: Sin2x-1=0 I thought I recognized that Sin2x is from the double angle identities chapter so I substituted [2CosSin] for Sin2x. So I ended up with 2CosSin=1 ( I moved the one over) ...and then I got stuck... am I...