Recent content by dflutedevil

see i just used the triangle to find the hypotenuse and then subtracted 17 from that. is that how i was supposed to do it? or am i way off?

uhm... don't know...so v=sqrt(2gh)

so is this right then... 1/2v^2=h thus... v=sqrt(2h)

I'm confused...I'm sorry. I guess I don't understand the concepts...so the h that i got = the potential and kinetic energy? but still the kinetic energy equation equals 1/2mv^2 which still requires mass?

well i got how high he was when he landed but how does that relate to potential energy. isn't that U=mgy. i don't have his mass? is there something I'm missing?

I just need some direction that's all..I'm not really good at this...I don't need the whole answer...just maybe some direction

A 17m--long vine hangs vertically from a tree on one side of a 10m--wide gorge, as shown in the figure. Tarzan runs up, hoping to grab the vine, swing over the gorge, and drop vertically off the vine to land on the other side. What minimum speed must he be running?

Two forces, both in the x-y plane, act on a 1.5 kg mass that accelerates at 7.3 m/s^2 in a direction 30 degrees counterclockwise from the x axis. One force has magnitude 6.8 N and points in the + x direction. Find the other force. Express it as a comma separated pair of components. I know...