What Is the Second Force Acting on a Mass in the x-y Plane?

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SUMMARY

The discussion focuses on calculating the second force acting on a 1.5 kg mass in the x-y plane, which accelerates at 7.3 m/s² at an angle of 30 degrees from the x-axis. Given that one force has a magnitude of 6.8 N directed along the +x axis, the net force can be determined using vector addition. The required second force can be calculated by applying trigonometric principles to find its components based on the resultant force derived from the mass and acceleration.

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  • Understanding of Newton's Second Law of Motion
  • Basic knowledge of vector addition
  • Familiarity with trigonometric functions and right triangles
  • Ability to resolve forces into components
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Two forces, both in the x-y plane, act on a 1.5 kg mass that accelerates at 7.3 m/s^2 in a direction 30 degrees counterclockwise from the x axis. One force has magnitude 6.8 N and points in the + x direction. Find the other force. Express it as a comma separated pair of components.

I know this seems easy but I'm just not getting it. Any help?
 
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You know mass and acceleration so you can find the resultant net force's magnitude

You know one component of the resultant force is just a vector of magnitude 6.8N at 0 degrees(on the x-axis)

So that vector + another vector you need to find = the resultant vector

You should know equations for deducing both the magnitude and angle of the second vector(they involve trig and right triangles), then you can use trig to get those components.
 
if it involves trig then of course it involves right angles
 

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