I obtained the black hole solution whose the metric function f(r) and scalar function ##\varphi(r)## are ;
##f(r)=\frac{1}{4}+\left(\frac{Z^{2}}{2r^{2}}\right)^{2}-\frac{1}{3}\Lambda r^{2}##
##\varphi(r)=\pm\left(\frac{1}{\sqrt{2}l}\right)r##
where ##Z##, ##\Lambda## and ##l## are just...
Very thanks to your reply.
Yes my question is whether or not
##∇_μ∇_ν∇^νF_{ab}=∇_ν∇^ν∇_μF_{ab}## where ##F_{ab}## is electromagnetic field tensor.
Can I simply think,
so d'Alembert operator ##∇_ν∇^ν## is invariant,
then Can I immediately write ##[∇_μ,\Box]=0##??