Recent content by Directrix

Thank you for all your replies! This solves my problem.

Ok, yes you're right. The only thing that troubles me is that 2 x 4 x 7! = 8!, am I heading the right way by doing the following? 8! - 7! x 2 - 6! x 4 - 5! x 8 - 4! x 16 = 26016 I'm not sure how many to add (because some do overlap), could someone maybe explain how I would find the number of...

Thank you for your reply. I think I have the right answer now, 8! - 7! x 2 = 30240 This assumes one couple is sitting together, but also includes arrangements when 2, 3, or all 4 couples sit together.

I'm stuck on the following question and I don't what to do, At a banquet hall, four couples are sitting along one side of a table. How many arrangements are possible if no one is sitting beside his or her partner. Any help appreciated.