Recent content by djc88

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    Hydraulic lift problem

    there are no changes to the density of the oil. the force is what i'm confused about. since on the opposite end, no additional mass is added, is the force acting upon that piston equivalent to part a? or do i have to find the new force, F2=F(A1/A2); where F=1360kg (mass of the car +person). I've...
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    Hydraulic lift problem

    i'm having difficulty with part C of this problem. A hydraulic lift has two connected pistons with cross-sectional areas 25 cm2 and 430 cm2. It is filled with oil of density 500 kg/m3. a) What mass must be placed on the small piston to support a car of mass 1300 kg at equal fluid levels...
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