Recent content by DKOli

^^^ this is wrong, should still be sum of x, but should also involve T. initial guess: ∅i+1 = { Ʃx + T + (n-m)∅i } / n ?

Right well Ill just call my complete data Z = (x1,...,xm,T) where T=(xm+1,...,xn) are censored/unobserved. Then my complete data log likelihood will just be: l(x) = nlog(∅) - Ʃx∅ all sums go from n starting at i=1 Then given the memoryless property we have E[X|X>=T] = T + 1/∅ (which...

So I can just say E(X) = 1/theta (from 1 - m, as its distribution is exponential) and write X_m+1 - X_N as T + Y_m+1 - T + Y_n where Y_i are iid to X_i (or was X_1 right, I assumed it was a typo) and thus the expectation of the censored data is simply T + 1/theta. If I solve as MLE I would...

For censored data. Random sample X1,...,Xn Censored such that x1,...xm are observed but xm+1,...,xn are not - we just know they exceed T. fx = exponential = theata exp(-theta.x) L = ∏ (from 1 going to m) f(x;theta) ∏ (m+1 - n) 1 - F(T;theta) Using F = int f I get L =...

Im in a rush and don't want to fool about with symbols. Google semi definite programs and look at a few of the papers. its the one that uses f(x)>=0 where fx= f0 + sum(xiFi) in relation to mine, the Fi's are Ai's and f0 is the b's. Its so i could solve the simple sdp using sdpa...

So my primal should be: min 3x + 4y x=A1 x + A2 y - c >= 0 c= diag(-12, 4, 0, 1) A1= diag(-3, 1, 0, 1) A2= diag(4, 2, 1, 0) I confirmed this with my lecturer. I then showed him the dual you gave but he said it was wrong. Didnt really go into it much but he said to start the...

I am comparing LP's and SDP's and have come across a lot of papers where they show all of the differences, but I am trying to put an lp is sdp form. The reason being I have solved an advanced sdp using an online solver and can solve basic/advanced lps on my pc, but I now want to take a lp and...

lol intensity=power/area - hope no1 used that 2day. How about you guys learn physics first before posting. r=500/i lux kOhm. keep it simple. The area for that equation is not going to be using a raduis of distance between source to ldr. That would find intensity within sphere NOT IN LDR...