Recent content by dmkeddy
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What Was the Take-Off Speed of the Long Jumper?
that is the vertical, there is no horizontal acceleration Vertical: Vi=? Vf=? a=-9.8m/s^2 t=? d=0 Horizontal: Vave=? t=? d=8.90m- dmkeddy
- Post #3
- Forum: Introductory Physics Homework Help
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What Was the Take-Off Speed of the Long Jumper?
Homework Statement An athlete executing a long jump leaves the ground at an angle of 30 degrees and travels 8.90m. What was the take-off speed? Homework Equations d(vertical)=(vi)(t) + 0.5at^2 The Attempt at a Solution 0=Vsin30t + (0.5)(-9.8)(t^2) I cannot solve for two separate...- dmkeddy
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- Replies: 3
- Forum: Introductory Physics Homework Help
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Athlete jumps at angle with distance find speed
travels horizontally 8.90m, no vertical displacement, time is unknown, how do I solve for two variables? Or what do I substitute velocity or time with to solve for the other?- dmkeddy
- Post #6
- Forum: Introductory Physics Homework Help
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Athlete jumps at angle with distance find speed
I'm having a similar problem: An athlete executing a long jump leaves the ground at an angle of 30 degrees and travels 8.90m. What was the take-off speed?- dmkeddy
- Post #4
- Forum: Introductory Physics Homework Help