Recent content by Doug

The horse may be cold but there's another way to beat it The probability of getting a 6 on the first roll is: \frac{1}{6} The probability of getting a 6 on the second roll given that we didn't get a 6 on the first is: \frac{5}{6}\cdot\frac{1}{6} The probability of getting a 6 on the...

If you know the acceleration you can just figure it out from that. Doug

Is it not the force required to accelerate a 1kg mass at 1m/s^2? Doug

Let's see: Total number of combinations is 6*6*6=216. Number of combinations with exactly one 6 is 25*3=75. Number of combinations with exactly two 6's is 5*3=15. Number of combinations with exactly three 6's is one. Thus the total number of combinations with at least one 6 is...

http://www-history.mcs.st-and.ac.uk/history/ Doug

Although we come up with the same answer your reasoning is more universal, shall we say

Then one of the endpoints of the interval takes the prize. Either R(100)>R(250) or vice-versa. Doug

The manufacturer wants to maximize profit thus he wants to maximize revenue. What you need to do is find the number of jackets p that maximizes revenue. The first and second derivatives of R(p) help you find that value. Once you know the number of jackets that maximizes revenue then you can...

Solve \frac {dR} {dp} = 0 for p Then you can use the second derivative test to see if R(p) is a maximum or minimum. Doug