Pulley with cylinder and distance

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The discussion centers on calculating the linear speed of a cylinder-pulley-block system after a block falls 2.5 meters, starting from rest with an acceleration of 2.98 m/s². Participants suggest using conservation of energy or integrating the acceleration equation twice to derive a distance formula. By substituting the known distance into the formula, one can find the time, which can then be used to calculate the velocity. The integration method is highlighted as a potentially effective approach to solve the problem. This method emphasizes the relationship between acceleration, distance, and velocity in the context of the system's motion.
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Hey, thanks for the help. I came up with acceleration = 2.98 m\s^2

One more quick one: If the cylinder-pulley-block system starts from rest, determine the linear speed of the system after the block falls
d=2.5 meters.

Should I use conservation of energy?
 
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If you know the acceleration you can just figure it out from that.

Doug
 
I have a suggestion although I'm not entirely sure it will work.

Take the equation you used to find the acceleration and integrate it twice with respect to time. This will give you a distance formula. Substitute in the value you are given for distance to find the value for time. Substitute that time value into the first integral and you should get the proper velocity.
 
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