Recent content by doxigywlz

Actually, I got the wrong answer again! 1.02 and it's supposed to be 1.2! Maybe that's a mistake... Looking forward to more help! : )

yes, i did ask but i didn't look! Thanks for the help, I'm sure it will help. Any help with the next problem?? My sister is even trying to help me with it and we are not getting anywhere! Just further into our block whole of physics torture!

okay, i did what you said for #1... but my answer is off . 18^2 =2(1.9)theta... I got 85.3 and then multiplied that by .012 for the radius and got 1.0236. The answer is 1.2m... Where did I go wrong? And for #2, I'm still totally confused and not getting the right answers

Okay, I first want to tell you that today is my birthday so if you want to doubley help me out, that would be great... so i put my homework off because it was my homework weekend and now I'm screwed because i can't figure out these last two problems. 1.) A coin with a diameter of 2.40 cm is...

pseudo, no-- it didn't work (unless I did it wrong)... Acceleration is meters per second squared or, in this case, radians per second squared... so how does that help me solve for time? 1.9=change in w over seconds squared.. i tried to solve for it, but i got it wrong.. please a...

Okay, I have this very EASY question (or so it appears) but I don't know how to figure out the time in this problem: a coin with a diameter of 2.4 cm is dropped on edge onto a horizontal surface. the coin starts out with an initial angular speed of 18 rad/s and rolls in a straight line...

thanks, by the way... that helped a lot

ooookkkkaaayyy... doesn't look like I'm getting going to get anywhere with this problem 2nite.

i'm really confused... i don't get it. i tried what you said but I'm still not getting the right answer.

okay, so then i have V1i = (112/12) Vf and then (12)(V1i)^2 = 12 V1f^2 + 100 V2f^2 + (150)(80)^2??

okay, i think i see what you mean. so... will it be m1v1 + m2v2 = (m1 + m2) vf ??

i hate to be a bother... but isn't that what i did?

oooooohhhhh yeah. thanks! let's see if i can get the answer now...

okay, more questions for me! this really, really easy question is not working out for me! A 90-kg fullback moving east with a speed of 5 m/s is tackled by a 95-kg opponent rnning north at 3m/s. what is their velocity just after the tackle? Perfectly inelastic, right? so (90)(5) +...

are you telling me that the first part of the kinetic energy is equal to zero? sorry,i'm a little confused...