Recent content by DrChinese

Yikes! I'm reaching back to post #1 in this thread!! 1. To be clear: The Bohmian spin observable - let's just call it spin - is some function of the particle's position and the positions/velocities/other properties of other particles. But for the experimental entangled spin rules to work...

1. No difference at all. 2. That is true for Ma (2012), yes, but is changing. The current experimental record is at least 57.9%. A BSM can normally be set to look for ##\{\Phi^+,\Phi^-\}## or for ##\{\Psi^+,\Psi^-\}##. You currently can't differentiate all 4 with equal success. They are...

1. This looks pretty good, Morbert. :smile: And it is consistent with Ma Fig 1. So on the H/V basis there is same 1 and 4 correlations for both ##\{\Phi^+,\Phi^-\}##, while for the other 2 bases they are opposite. For now, assume I agree with you. And thanks for taking the time to explain...

More great questions. It's amazing how quickly a few words here or there can point in different directions without me realizing it. 1. A little disagreement. @Morbert uses the lingo "##\{\Phi^+,\Phi^-,HV,VH\}##" from Ma differently than I with "##\{\Phi^+,\Phi^-,\Psi^+,\Psi^-\}##. a...

It may be helpful to simply jump to the bottom for the summary. :smile: 1. ##\Phi^+## generally yields opposite Alice/Bob correlation to ##\Phi^-##, right? Actually this is a point is not entirely clear in Ma. I have always been under the impression that ##\Phi^+## and ##\Phi^-## yield...

I understood Alice and Bob are measuring on the HV basis. If you look at Ma Fig. 3, a (which is ##\Phi^-##) - there is correlation. You have that too, all good. But you also show correlation for ##\Phi^+## in your 3 & 4. On your graph 1, you show anti-correlation. I realize your graph 1 is...

Note that the outputs you call "HV,VH" can also be labeled "|Ψ−>, |Ψ+>" since these are the other 2 Bell states. These cannot, however, be optically distinguished at this time.

Wow Morbert, nice work. I need you to come over and do a few of these for me. - First graph (Alice/Bob "same basis"): I agree. - Second graph (Alice/Bob "mutually unbiased bases"): I agree. Alice and Bob never show any entanglement on mutually unbiased bases. - Third graph and fourth graphs...

FYI: As it happens, photons carrying time stamp information (usually arrival time) can be distinguished - even if otherwise indistinguishable. This particular point is explicitly used the the Megidish et al paper Fig. 3: "(c) when the projection fails due to temporal distinguishability."

1. I also use the term "mutually unbiased bases". Here I used the other term, although they are not precisely the same. 2. Good question. The answer is: Victor's Bell State Measurement, leading to ##\Phi^+## and ##\Phi^-## as you say, can be done on any basis. If Victor were to choose H/V...

Any 4 independent events can be modeled as any permutation of any 1, 2, 3 or 4 of them. I think you are smart enough to take it from there. Who said they were? Just read what I wrote. I do not plan to continue discussing something we've discussed ad nauseum. You are harassing me. I am...

In the Bohmian view, since spin is an observable but not an independent property of an electron: The parallel to the Ma experiment would be having the "BSM" be on the spin-x basis; and then having the spin-x, spin-y, and spin z components all become independently entangled (noting they are...

If you believe |Ψ〉1234 = |Ψ−〉12⨂|Ψ−〉34 leads to (2) when no BSM has yet occurred, then by extension: |Ψ〉12345678 = |Ψ−〉12⨂|Ψ−〉34⨂|Ψ−〉56⨂|Ψ−〉78 leads to: a) |Ψ〉1234 = 12(|Ψ+〉14⨂|Ψ+〉23 − |Ψ−〉14⨂|Ψ−〉23 − |Φ+〉14⨂|Φ+〉23 + |Φ−〉14⨂|Φ−〉23) b) |Ψ〉1256 = 12(|Ψ+〉16⨂|Ψ+〉25 − |Ψ−〉16⨂|Ψ−〉25 − |Φ+〉16⨂|Φ+〉25...

Don't need to. If a) is true, by your logic b) and c) are equally true. Before the BSM, nothing has happened! Sorry if you can't see the algebraic substitution clearly.

Sure. i) For a Spin 1/2 particle, say an electron, we have: spin-x, spin-y, and spin z. All 3 are independent degrees of freedom. Hopefully no one will question this point. ii) For a Spin 1 particle, say a photon, we have: H/V polarization, L/R polarization, and +/-* polarization. Like with...