Recent content by drsauce

If Iv got this right, your saying that ψ0(x) = C sin (xπ/a)exp[it(E-ω)]

ah. I was assuming A and B to be functions, and that was making things a lot more complex.

Could you show how you do this part please. I'm assuming you integrate ∫ψ(A-iB)ψ* but I am not sure where to begin on this and I feel I'm missing something very basic