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Proving detA = λ1...λn for Real Eigenvalues
Homework Statement Let A be nxn matrix, suppose n has real eigenvalues,λ1,...,λn, repeated according to multipilicities. Prove that detA = λ1...λn. Homework Equations The Attempt at a Solution I started by applying the definition, Av = λv, where v is an eigenvector. then I just dun...- dsyh
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- Eigenvalues
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- Forum: Calculus and Beyond Homework Help