Recent content by durandal

I figured it out, I made a mistake when I assumed that the time shift was ##(t-4)##, but the function can be rewritten as ##\sin(4t-4) = \sin(4(t-1))##, with time shift ##(t-1)##. The transform then becomes ##\frac{\pi}{j}e^{-j \omega}(\delta(\omega -4) - \delta(\omega + 4))##, which is correct.

I tried inputting this solution but it was incorrect. I can't see where a factor of ##\sqrt{2\pi}## would come from?

This is my attempt at a solution. I have used Eulers formula to rewrite the sine function and then used the Fourier transform of complex exponentials. My solution is not correct and I don't understand if I have approached this problem correctly. Please help. $$ \mathcal{F}\{\sin (4t-4) \} =...

Thank you very much. I found the eigenvectors to be v1 = [1 , -Zc^-1] and v2 = [1 , Zc^-1]. My professor verified it, but he also said that the eigenvectors could be found just by "looking" at the matrix itself. I have asked him about this, but he hasn't answered me. Do you have any idea which...

I have tried row reduction to solve for the first eigenvector but I don't feel like I get any closer to the solution: